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Factoring Trinomials
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12 = 1 • 12

= 2 • 6

= 3 • 4

Step 3: Which pair adds up to 11?

Step 1: Multiply 3 • 4 = 12 (the leading coefficient & constant).

None of the pairs add up to 11, this trinomial can’t be factored; it is PRIME.

Slide 16

Factor each trinomial, if possible. The first four do NOT have leading coefficients, the last two DO have leading coefficients. Watch out for signs!!

Factor each trinomial, if possible. The first four do NOT have leading coefficients, the last two DO have leading coefficients. Watch out for signs!!

1) t2 – 4t – 21

2) x2 + 12x + 32

3) x2 –10x + 24

4) x2 + 3x – 18

5) 2x2 + x – 21

6) 3x2 + 11x + 10

Factor These Trinomials!

Slide 17

Solution #1:

Solution #1:

t2 – 4t – 21

1) Factors of -21:

1 • -21, -1 • 21

3 • -7, -3 • 7

2) Which pair adds to (- 4)?

3) Write the factors.

t2 – 4t – 21 = (t + 3)(t - 7)

Slide 18

Solution #2:

Solution #2:

x2 + 12x + 32

1) Factors of 32:

1 • 32

2 • 16

4 • 8

2) Which pair adds to 12 ?

3) Write the factors.

x2 + 12x + 32 = (x + 4)(x + 8)

Slide 19

Solution #3:

Solution #3:

x2 - 10x + 24

1) Factors of 32:

1 • 24

2 • 12

3 • 8

4 • 6

2) Which pair adds to -10 ?

3) Write the factors.

x2 - 10x + 24 = (x - 4)(x - 6)

None of them adds to (-10). For the numbers to multiply to +24 and add to -10, they must both be negative!

-1 • -24

-2 • -12

-3 • -8

-4 • -6

Slide 20

Solution #4:

Solution #4:

x2 + 3x - 18

1) Factors of -18:

1 • -18, -1 • 18

2 • -9, -2 • 9

3 • -6, -3 • 6

2) Which pair adds to 3 ?

3) Write the factors.

x2 + 3x - 18 = (x - 3)(x + 18)

Slide 21

Solution #5:

Solution #5:

2x2 + x - 21

1) Multiply 2 • (-21) = - 42; list factors of - 42.

1 • -42, -1 • 42

2 • -21, -2 • 21

3 • -14, -3 • 14

6 • -7, -6 • 7

2) Which pair adds to 1 ?

3) Write the temporary factors.

2x2 + x - 21 = (x - 3)(2x + 7)

( x - 6)( x + 7)

4) Put “2” underneath.

5) Reduce (if possible).

3

6) Move denominator(s)in front of “x”.

( x - 3)( 2x + 7)

Slide 22

Solution #6:

Solution #6:

3x2 + 11x + 10

1) Multiply 3 • 10 = 30; list factors of 30.

1 • 30

2 • 15

3 • 10

5 • 6

2) Which pair adds to 11 ?

3) Write the temporary factors.

3x2 + 11x + 10 = (3x + 5)(x + 2)

( x + 5)( x + 6)

4) Put “3” underneath.

5) Reduce (if possible).

2

6) Move denominator(s)in front of “x”.

( 3x + 5)( x + 2)

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