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PROJECTILE MOTION Senior High School Physics

Lech Jedral

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Projectile Motion:

Motion through the air without a propulsion

Examples:

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Part 1. Motion of Objects Projected Horizontally

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v0

x

y

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x

y

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x

y

Slide 7

x

y

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x

y

Slide 9

x

y

Motion is accelerated

Acceleration is constant, and downward

a = g = -9.81m/s2

The horizontal (x) component of velocity is constant

The horizontal and vertical motions are independent of each other, but they have a common time

g = -9.81m/s2

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ASSUMPTIONS:

x-direction (horizontal): uniform motion

y-direction (vertical): accelerated motion

no air resistance

QUESTIONS:

What is the trajectory?

What is the total time of the motion?

What is the horizontal range?

What is the final velocity?

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Frame of reference:

Equations of motion:

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x = v0 t

y = h + ½ g t2

Eliminate time, t

t = x/v0

y = h + ½ g (x/v0)2

y = h + ½ (g/v02) x2

y = ½ (g/v02) x2 + h

Parabola, open down

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Total Time, Δt

y = h + ½ g t2

final y = 0

ti =0

tf =Δt

0 = h + ½ g (Δt)2

Solve for Δt:

Total time of motion depends only on the initial height, h

Δt = tf - ti

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Horizontal Range, Δx

final y = 0, time is the total time Δt

Horizontal range depends on the initial height, h, and the initial velocity, v0

x = v0 t

Δx = v0 Δt

- Introduction
- Analysis of motion
- Trajectory
- Velocity
- Final velocity
- Maximum Height
- Projectile Motion – Final Equations
- Projectile motion - summary

- Sound
- Madame Marie Curie
- Health Physics
- Ch 9 Nuclear Radiation
- Newton's Laws
- Motion
- Mechanics Lecture

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