Keep in mind that, because some of our pairs are not identical factors, we may have to exchange some pairs of factors and make 2 attempts before we can definitely decide a particular pair of factors will not work.
Example
Continued.
Slide 24
We will be looking for a combination that gives the sum of the products of the outside terms and the inside terms equal to 20x.
{x, 25x} {1, 4} (x + 1)(25x + 4) 4x 25x 29x
(x + 4)(25x + 1) x 100x 101x
{x, 25x} {2, 2} (x + 2)(25x + 2) 2x 50x 52x
Factoring Polynomials
Example Continued
Continued.
Slide 25
Check the resulting factorization using the FOIL method.
(5x + 2)(5x + 2) =
= 25x2 + 10x + 10x + 4
= 25x2 + 20x + 4
So our final answer when asked to factor 25x2 + 20x + 4 will be (5x + 2)(5x + 2) or (5x + 2)2.
Factoring Polynomials
Example Continued
Slide 26
Factor the polynomial 21x2 – 41x + 10.
Possible factors of 21x2 are {x, 21x} or {3x, 7x}.
Since the middle term is negative, possible factors of 10 must both be negative: {-1, -10} or {-2, -5}.
We need to methodically try each pair of factors until we find a combination that works, or exhaust all of our possible pairs of factors.
Factoring Polynomials
Example
Continued.
Slide 27
We will be looking for a combination that gives the sum of the products of the outside terms and the inside terms equal to 41x.
{x, 21x}{1, 10}(x – 1)(21x – 10) –10x 21x – 31x
(x – 10)(21x – 1) –x 210x – 211x
{x, 21x} {2, 5} (x – 2)(21x – 5) –5x 42x – 47x
(x – 5)(21x – 2) –2x 105x – 107x
Factoring Polynomials
Example Continued
Continued.
Slide 28
{3x, 7x}{1, 10}(3x – 1)(7x – 10) 30x 7x 37x
(3x – 10)(7x – 1) 3x 70x 73x
{3x, 7x} {2, 5} (3x – 2)(7x – 5) 15x 14x 29x
Factoring Polynomials
Example Continued
Continued.
Slide 29
Check the resulting factorization using the FOIL method.
(3x – 5)(7x – 2) =
= 21x2 – 6x – 35x + 10
= 21x2 – 41x + 10
So our final answer when asked to factor 21x2 – 41x + 10 will be (3x – 5)(7x – 2).
Factoring Polynomials
Example Continued
Slide 30
Factor the polynomial 3x2 – 7x + 6.
The only possible factors for 3 are 1 and 3, so we know that, if factorable, the polynomial will have to look like (3x )(x ) in factored form, so that the product of the first two terms in the binomials will be 3x2.