The Chemistry of Acids and Bases

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Amount of NaOH in final solution must also = 0.15 mol NaOH

Volume of final solution =

(0.15 mol NaOH) / (0.50 M) = 0.30 L

or 300 mL

Slide 72

PROBLEM: You have 50.0 mL of 3.0 M NaOH and you want 0.50 M NaOH. What do you do?

Conclusion:

add 250 mL of water to 50.0 mL of 3.0 M NaOH to make 300 mL of 0.50 M NaOH.

Slide 73

A shortcut

M1 • V1 = M2 • V2

Preparing Solutions by Dilution

Slide 74

You try this dilution problem

You have a stock bottle of hydrochloric acid, which is 12.1 M. You need 400. mL of 0.10 M HCl. How much of the acid and how much water will you need?